?a?????t 3dd13003 k8 ?????1?????????e???1 1 ?????? 3DD13003K8 1 npn e 1| a?a1?? ?1 ?a ?? ??? ? ?? ?1| a?a1?? a ??????a ??e?????1?? a??e? ?a1???? o?1??? ??e?o? ?a??e?o? ae?? t o -220ab 2 ??e? 2.1 ???t? 3y?e1?? t am b = 25 2? y ?? 3? ?o? ???? ??? ???? - l?????1 v ce0 4 0 0 v ???? - ? ????1 v cb0 7 0 0 v l??? - ? ????1 v eb0 9 v ????? i c 1 . 5 a ta = 2 5 2 o?1|a tc = 2 5 p tot 50 w ??a t j 1 5 0 ???a? t stg - 5 5 150 2.2 ?2?y 3y?e1?? t am b = 25 1? ? ? 2? y ?? 3? ? o? 2a ? ? ?t ?e? ?e ?? ??? ???? - ??????1? i cb0 v cb =700v , i e =0 0 . 1 m a l??? - ??????1? i eb0 v eb =9v , i c = 0 0 . 1 m a 12l????y????? ??2?? h fe a v ce =5v , i c = 0 . 5 a 8 4 0 e?? ?a h fe 1 ?? ? ?a h fe2 ? h fe1/ h fe2 h fe1 :v ce =5v , i c =5m a h fe2 .v ce =5v , i c =250m a 0 . 7 5 0 . 9 ???? - l???o??1 v ce sat a i c =1a, i b =0.25a 0 . 8 v ? ?? - l???o??1 v be sat a i c =1a, i b = 0 . 2 5 a 1 . 2 v ?a???? t f 0 . 5 s ???? t s v cc =100v , i c =1a i b1 =-i b2 =0.2a 2 . 5 s ???a f t v ce =10v , i c =100m a f=1mhz 5 m h z a : a?3?2a? tp 300 s, 2% 2.54 2.54 1.4 max b c e 10.7m a x 16.5m ax 12.5m in 0.56 m 4.8 max 3. 84 6.9 m ax ?t?y?a???1ye?t1??? ?? ?-????t?yeo?aa 14 o? ?? 05 10 58 07 22 8-22 68 229 9 ??? 05 10 580 03 60 ? 1 3 12 2 3
?a?????t 3dd13003 k8 3 ?e???? 0. 1 0. 0 1 1 i c (a ) 1 10 10 0 v ce (v ) 10 0 0 0 50 p tot (w) 20 30 t ( ) 10 40 p tot - t 1????? 2?1?? ( ? ) t case =25 p tot - t case p tot - t am b 0.0 1 1 0.1 1 i c (a ) h fe 10 0.8 10 1 v be sat (v ) 1.2 i c (a ) h fe - i c 1????? v besat - i c 1????? t am b =25 v ce =5v t am b =25 i c /i b =4 t am b =25 i c /i b =4 v cesat - i c 1????? v cesat (v) 1 0.1 0 . 1 1 i c (a) ? 2 3 12 2 3
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